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Christmas Calcudoku 20122013 http://www.calcudoku.org/forum/viewtopic.php?f=16&t=389 
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Author:  clm [ Wed Dec 26, 2012 10:56 pm ] 
Post subject:  Christmas Calcudoku 20122013 
Christmas Calcudoku 20122013. Accepting the Patrick’s invitation (“Calcudoku General”, thread “Lowering level of participation”) reproduced here: pnm wrote: clm wrote: Meanwhile I am sure you will be waiting the special "Christmas" and "New year" puzzles that Patrick must be prepearing ... at that time pse get the 25 points each. I'm quite busy though, and visiting family over the holidays. Feel free to submit a candidate puzzle (file format described here: viewtopic.php?f=2&t=48&p=1577#p1577 ) I have prepeared this puzzle. It has not been translated to the format referred since it contains new operators (that the software would not recognize), the linear combinations, that I propose as a new type of operators for the future. 
Author:  nicow [ Fri Dec 28, 2012 4:41 pm ] 
Post subject:  Re: Christmas Calcudoku 20122013 
I have to admit, that I do not understand how 2, +2 and x2 could be a 'linear combination'...? 
Author:  clm [ Fri Dec 28, 2012 9:02 pm ] 
Post subject:  Re: Christmas Calcudoku 20122013 
nicow wrote: I have to admit, that I do not understand how 2, +2 and x2 could be a 'linear combination'...? Thanks for your interest and comment, initially I have intentionally left the things a little "dark" in order to make attractive the clarification of what's that of "linear combination". The operation itself is a subtraction "", an addition "+" and a product "x"; for instance, in the cage "48x2", 48 is the final result, the operation is a multiplication, and the final 2 means that the rest of the operands are multiplied by 2, in this particular case (two cells) there is only one operand affected, that is, a x (2b), so 4 and 6 are the operands, or in other words [4,6] is the only valid combination since 4 x (2x6) or 6 x (2x4) produces 48 in both cases. Now, let's suppose we had the result "11+2" (two cells), we would have these possibilities: [1,5], [1,9], [2,7], [3,4], [3,5], that is, one of the numbers plus twice the other number sums 11. We could say that the operation a + 2b is a linear combination. A cage "12", in three cells, can be obtained with [1,1,5] since 5  2x1  2x1 = 1. Finally, if we had "27+3" in a 7x7 Calcudoku (in the proposed puzzle there are not cages with a 3 after the operator), in three cells, what we propose is: a + 3b + 3c, so for instance [1,3,7] is a solution since 3 + 3x1 + 3x7 = 27, but another solution, for instance, could be [3,4,6] since 6 + 3x3 + 3x4 = 27, etc. 
Author:  pnm [ Mon Dec 31, 2012 12:15 pm ] 
Post subject:  Re: Christmas Calcudoku 20122013 
Just solved it, cute puzzle, not difficult It'd be pretty easy to update the software to support this type of puzzle. Most work would be in supporting the "special operator", because it's no longer a single character. Maybe also use a different character to signify the linear combination, the 2 is a bit confusing (e.g. when you read "10+2" you don't immediately think "a + 2b = 10")(maybe write out the whole thing: 10 (a+2b) ) 
Author:  clm [ Mon Dec 31, 2012 9:38 pm ] 
Post subject:  Re: Christmas Calcudoku 20122013 
pnm wrote: Just solved it, cute puzzle, not difficult It'd be pretty easy to update the software to support this type of puzzle. Most work would be in supporting the "special operator", because it's no longer a single character. Maybe also use a different character to signify the linear combination, the 2 is a bit confusing (e.g. when you read "10+2" you don't immediately think "a + 2b = 10")(maybe write out the whole thing: 10 (a+2b) ) Thanks for your time, I am glad to hear that, it means that the solution is unique. Yes, your idea for the notation is much better and clearer when using a linear combination inside a cage; in fact I was thinking in the past in the possibility of different types of linear combinations like, using this last notation, could be of course "a + 2b" (asuming the generalization to "a + 2b + 2c" if three cells in the cage, etc.) or "a + 3b" ("a + 3b + 3c + ... " if several cells) but also "a + 2b + 3c" or "3a  b", for instance, giving only two additional examples. The notation is always the problem because it occupies some space in the top of the cell, in fact, in the past I was thinking in things like 29+23 [with your notation it would be 29 (a + 2b + 3c)], for instance, with three cells, for the case 2 + 2x3 + 3x7 = 29 (so the combination [2,3,7] would be a solution in a 7x7 puzzle, with other solutions like [6,4,5] = 6 + 2x4 + 3x5 = 29, etc.). Happy 2013. 
Author:  veryevilking [ Fri Dec 06, 2013 4:22 pm ] 
Post subject:  Re: Christmas Calcudoku 20122013 
or a 20x20 with christmas? 
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