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 Author: pnm  [ Thu Mar 27, 2014 9:04 pm ] Post subject: today's 4x4 difficult Of the regular puzzles I enjoy doing the 4x4 difficult, trying tofind the shortest "reasoning only" path to a solution. So whatis the shortest path for today's?

 Author: clm  [ Thu Mar 27, 2014 11:53 pm ] Post subject: Re: today's 4x4 difficult pnm wrote:Of the regular puzzles I enjoy doing the 4x4 difficult, trying tofind the shortest "reasoning only" path to a solution. So whatis the shortest path for today's? .... Let's see this: Since a1 + a2 + a3 = 9 (addition rule to column 1) >>> b2 = 2 (= 11 - 9) >>> b4 = 3, c4 = 2.Since d2 + b3 + c3 + d3 = 10 (= 15 - 3 - 2) and, at the same time,a3 + b3 +c 3 + d3 = 10, we have d2 = a3 = 3, because the "3" is the only number that can be placed simultaneously in d2 and a3.The rest is very fast: row 2: c2 = 1, a2 =4column 2: c1 = 3, c3 =4, ... , the rest is obvious.

 Author: kozibrada  [ Fri Mar 28, 2014 5:42 am ] Post subject: Re: today's 4x4 difficult clm wrote:Since d2 + b3 + c3 + d3 = 10 (= 15 - 3 - 2) and, at the same time,a3 + b3 +c 3 + d3 = 10, we have d2 = a3 = 3, because the "3" is the only number that can be placed simultaneously in d2 and a3.I solved this step differently.b2 = 2, of course. Before b4 and c4 I focused on 2 upper cages. They have a sum 20 (= 2 rows), thus d2 = a3.However, clm’s practice is probably better of the analytical view (1 row vs. 2 "my" rows)…

 Author: pnm  [ Fri Mar 28, 2014 9:51 am ] Post subject: Re: today's 4x4 difficult clm wrote:Let's see this: Since a1 + a2 + a3 = 9 (addition rule to column 1) >>> b2 = 2 (= 11 - 9) >>> b4 = 3, c4 = 2.Since d2 + b3 + c3 + d3 = 10 (= 15 - 3 - 2) and, at the same time,Those were my steps too, but after that I like:because those cells sum to 10, there can not be two "1"'s in there,so the 9+ cage must have two,so c2=1

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