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|Difficult 6x6 July 29
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|Author:||marblevolcano [ Fri Jul 29, 2016 1:36 am ]|
|Post subject:||Difficult 6x6 July 29|
New pattern in the 6x6's...
Alright, so this one was pretty difficult, but I somehow managed to get it without guessing.
-E6 must be 2 because the only possible combination in the 14+ cage is [3,5,6]. This means f6=4.
-D6 must be 5 because the 16+ cage contains [1,2,3,4,6]. This means that the rest of the 15+ cage contains [1,3,6], and 6 cannot go in c6 because of the 6 in c1. This leaves only 3 and 1.
-The possible combinations for the 9+ cages are [2,3,4], [1,3,5], and [1,2,6]. Because of the 6 in c1, the c-column cage cannot contain [1,2,6], and if it contained [1,3,5] then nothing could go in c6. This means the c-column 9+ must contain [2,3,4], leading c6 to have 1 and c5 to hold 5.
-The combination in the 5th row 9+ cage is [1,3,5] because of the 5 in c5.
-Because of the 5 in a3 and the fact that there must be a 3 in a5 or a6, the 1- cage at a1a2 must be [1,2], with the 2 in a1 and the 1 in a2. From here, you can find the bottom left foursome, leading a4 to contain 4. From here the rest of the puzzle can be solved without care for cages. The end!
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