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8x8 medium 18th Oct. https://www.calcudoku.org/forum/viewtopic.php?f=18&t=633 |
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Author: | sica [ Sat Oct 18, 2014 3:33 pm ] |
Post subject: | 8x8 medium 18th Oct. |
I think that this puzzle has a mistake. I can't understand how over 200 users solve it. a3=336x=7x48 b4=21x=7x3 a2=5 So a1=105x=3x5x7, 7 can be only on c1, 5 can be on b1 and 3 can be on a1. e8=14x=7x2 c8=6x=6x1 or 3x2 but there is already a 2 on this row so c8=6x1 a7=384x=64x6=8x8x6x1 or 8x8x3x2 On row 8 there are already 1, 2, 6 and 7 and we must write an 8 and a (6 or 1) or (3 or 2). The only one not used on this row is 3. But we can't use 3 becouse there is one on a1 and anotherone on column b (b4 or b5). |
Author: | wjgjr [ Sat Oct 18, 2014 4:19 pm ] |
Post subject: | Re: 8x8 medium 18th Oct. |
Puzzle spoilers included: a7 = 384x = 8x6x4x2 as well, which does not violate any of the constraints you listed. |
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