View unanswered posts | View active topics It is currently Fri Nov 28, 2014 6:50 am



← Back to the Calcudoku puzzle page




Reply to topic  [ 2 posts ] 
 march 12 9x9 cages of 27+ and 31+ 
Author Message

Posted on: Mon Mar 12, 2012 11:39 pm




Posts: 289
Location: Ladysmith, BC, Canada
Joined: Thu May 12, 2011 11:37 pm
Post march 12 9x9 cages of 27+ and 31+
Need a solving strategy for determination of cells in the 27+ and 31+ cages in the 9x9 of March 12.....any help would be appreciated........Ken


Profile

Posted on: Tue Mar 13, 2012 12:28 am




Posts: 585
Joined: Fri May 13, 2011 4:51 pm
Post Re: march 12 9x9 cages of 27+ and 31+
beaker wrote:
Need a solving strategy for determination of cells in the 27+ and 31+ cages in the 9x9 of March 12.....any help would be appreciated........Ken


If you continue a little bit from the process I have sent (in the other thread) for that puzzle you will quickly determine those cages, i.e.: "14+" = [6,8] >>> d9 = 6, e9 = 8, e5 = 4 (d5 = 7) >>> "7+" = [1,6] >>> h5 = 6, i5 = 1, g1 = 6.
Also g2 = 3 (g3 = 8), c1 <> 4 (because it would not be possible c2 + d2 = 12, that is, the combinations 3-9, 4-8 or 5-7). Then the 4 of row 1 goes to h1.
Also c1 <> 9 (it is not possible to obtain 7 with c2 + d2 due to f2 = 2, g2 = 3 and h2 = 1) so i1 = 9. Now i2 + i3 = 8 >>> i2-i3 = [3,5] >>> i2 = 5, i3 = 3. You have totally finished the cage "27+". Additionally c1 = 3.
Now, i6-i7-i8 = [2,7,8] >>> g8 + h8 = 14 >>> g8-h8 = [5,9] (8's in g3 and h4) then h8 = 5, g8 = 9. Also i6 = 2, etc. ...(i.e., d3 = 1, d4 = 3, c4 = 7, ... ).


Profile
Display posts from previous:  Sort by  
Reply to topic   [ 2 posts ] 

You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum

Search for:
Jump to:  
All forum contents © Patrick Min, and by the post authors.

Forum software phpBB © 2000, 2002, 2005, 2007 phpBB Group.
Designed by STSoftware.