https://logic-masters.de/Raetselportal/ ... ?id=000BEB

]]>

I find the Wed 10 x 10s are usually easy, and every 4 to 8 weeks there is a more challenging puzzle.

]]>

beaker wrote:

Patrick.....I have been thinking for the past week that we need a dislike button especially after today with the mod puzzle....too many cages with mod in them

I struggled with this one for quite a while. Only got it finished a few minutes ago, with about half an hour to spare before today’s deadline.

]]>

]]>

I think I needed to do a similar calculation in relation to the right hand side. But the puzzle worked out without too many hitches. I did it in one go and it took me just under 30 minutes. I know that sounds like a long time to spend on one puzzle, but I doubt I solve many of the Tuesday 9x9s in less than that!

]]>

eclipsegirl wrote:

I loathe the particular pattern. It is the hardest of the various 9 x 9 patterns.

Its been a very long time since we have seen that pattern.

It sounds like we also need a "dislike" button next to the "+"

(or even a "loathe" button )

]]>

eclipsegirl wrote:

I just wanted to congratulate the 97 people who solved it.

It was tough.

I loathe the particular pattern. It is the hardest of the various 9 x 9 patterns.

Its been a very long time since we have seen that pattern.

At the beginning I was scared of the puzzle, when I saw the pattern and the difficulty level (121!), and I was absolutely stuck once filled the "obvious" cells. Every cage had multiple possible combination, especially the multiplication ones on the left (columns a, b, c, d).

At a certain point I remembered a way to approach the diagram not so common, which I had read in one of the introductions in the Patrick’s books: you can’t only use the “addition” tool (every column or row has 45 as sum of the first 9 numbers) but also the “multiplication” tool: every column or row has 1×2×3×4×5×6×7×8×9 = 9! as product of the first 9 numbers, so two columns have (9!)^2, three columns have (9!)^3 and so on. These are huge numbers, but getting the number of the first three columns (9!)^3 and dividing it by the three products in there and the other numbers already inserted, I got a “small” product that, divided in factors, gave me a smaller number of possible combinations for the remaining cells of the columns a, b, and c. Above all, combining the “multiplication” way with the “addition” one, I got very few possibilities for the two 3024× and 180×. Just two for the 3024× and two for 180×.

I put the two for 3024× randomly in both cages, but soon I understood that it was the wrong choice, so I inverted the two combination (at that point the 180× was unique) and went on. I can’t say that at this point it was “easy”, but at least it was more manageable… so, at the end I succeed within midnight of Tuesday! I couldn’t believe it (and I can’t believe it till now! )

]]>

I loathe the particular pattern. It is the hardest of the various 9 x 9 patterns.

Its been a very long time since we have seen that pattern.

]]>

]]>

1) rule of parity: F6 = 46; E6 = 246

2) D7 ≠ 2 (due to a conflict with FG6)

3) 17+ cage can only be 737 or 746

4) AB1 ≠ 74 (due to D1 = 47) nor ≠ 36 (→ CG2 both = 6)

5) crucial (in my opinion) hi/lo decision on F6: if F6 = 4 → A6 = 2 → A5 can be 3 or 7…

a) if 3 → AB1 = 14; A2 = 7 → no possible combination for the A2 cage

b) if 7 → AB1 = 14; A2 = 3 and B23 must contain 7 (due to two 7’s in rows 4 and 5), which gives together another 4 for col. B

→ → → F6 ≠ 4 = 6

6) 17+ cage ≠ 737 (otherwise two 5’s in CD6) = 746

7) hidden triple (123) in AEF1 → E2 = 12345

8) 7 in col. E must be in E45 → E45 = 67

9) X-wing on 7 in EF45 → A5 ≠ 7 nor A2 ≠ 7 (due to the 7 forced into B23), thus A6 = 7

10) rule of parity: A3 = 6

11) three 6’s in rows 1, 2 and 3 → B23 can only be 457

12) hidden pair (36) in B45; the rest is easy.

EDIT: Steps 6) and 7) can be ignored by using an argument that if the E1 cage contains 7, then a sum of all four top cages (even if AB1 = only 1–4) would be 47, which would force a sum of 19 into CEG2 – impossible (max. 18) → 7 in col. E must be in E45. Etc…

]]>

skeeter84

]]>

These are the puzzles that make me anxious. I know I am struggling. I NEED to get the dailies done.

I also need to calm down. I have to leave this puzzle, for now. (That is painful for me.)

I do the following:

a) Finish ALL the other dailies, maybe even the EXTRA but the EXTRA can always wait.

Doing the EXTRA depends on time remaining before the clock resets, the ease of the EXTRA, and my anxiety level (Am I calmer?, Can I revisit that challenging puzzle?).

b) Return to the challenging puzzle. Look for a 2nd option to use T & E. Work it through. You may to find a 3rd option, or redo the puzzle from the beginning. That method always worries me due to time, but sometimes it is the best method.

If you need to redo the puzzle: Be savage with your assumptions. Why did you make this choice? Are you sure, you know there is an issue with the puzzle, could you have been wrong?

Double check your assumptions. I usually find that is where the error occurred.

]]>

eclipsegirl wrote:

NOOOOO

Please NO.

I guess that's a no then

]]>