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today's (June 12th, 2022) 4x4 difficult is tricky
https://www.calcudoku.org/forum/viewtopic.php?f=16&t=1438		 Page 1 of 1
Author:  pnm  [ Sun Jun 12, 2022 10:07 pm ]
Post subject:  today's (June 12th, 2022) 4x4 difficult is tricky
Someone asked about this puzzle on youtube, my reply copied here:

Image

That is quite a tricky one.

Here is the puzzle for reference: https://i.imgur.com/nDzx7Kw.png

I think a first step is to realize that both "2-" cages have to have the same numbers (!)
So either both 1,3, or both 2,4.

If they are both 1,3, then the sum of all cages except for the "1-" cage is 13 + 10 + 4 + 4 = 31,
which leaves 9 for the "1-" cage, which isn't possible.

If they are both 2,4, then this leaves 5 for the "1-" cage, which is possible, and can only be 2,3.

I'll probably do a short video on this puzzle as well, thanks for pointing it out :-)


If people know a quicker path to the solution, please post it here [thumbup]
Author:  guidocram  [ Sun Jun 12, 2022 11:35 pm ]
Post subject:  Re: today's (June 12th, 2022) 4x4 difficult is tricky
> "I think a first step is to realize that both "2-" cages have to have the same numbers (!)"

How is this mandatory?
Author:  mparisi  [ Mon Jun 13, 2022 12:43 am ]
Post subject:  Re: today's (June 12th, 2022) 4x4 difficult is tricky
guidocram wrote:
> "I think a first step is to realize that both "2-" cages have to have the same numbers (!)"

How is this mandatory?

If, for example, one of the cages is 2,4 then the other two cells in the row/column are 1,3,so the other cage can't be 1,3.
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