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Today's (12/31/2012) 7x7 difficult
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Posted on: Mon Dec 31, 2012 2:29 am

Posts: 93
Joined: Sat May 14, 2011 1:08 am
Today's (12/31/2012) 7x7 difficult
I believe I have solved this puzzle, but the 1^ cage in the middle is being flagged as incorrect with 1,5,7,7 as its contents -- integer overflow perhaps?

Posted on: Mon Dec 31, 2012 2:40 am

Posts: 193
Joined: Tue May 24, 2011 4:55 pm
Re: Today's (12/31/2012) 7x7 difficult
Same. And while all other puzzles today have been solved a number of times, the counter to the left of this one reads "(solved 0 time(s) so far)".

Posted on: Mon Dec 31, 2012 3:00 am

Posts: 713
Joined: Fri May 13, 2011 6:51 pm
Re: Today's (12/31/2012) 7x7 difficult
Same problem. Possible overflow in the calculation of powers depending on the sequence followed by the software, since (5 ^ 7) ^ 7 = 1,776... e+34. Consequently, the correct combination c3 = 7, d3 = 1, c4 = 5, d4 = 7 is not accepted as valid giving the red indication in cage 1^. At this time still 0 solutions as observed by bram. Suggestion: To modify the operation to 20+, for instance.

Posted on: Mon Dec 31, 2012 4:43 am

Posts: 2
Joined: Sun Dec 18, 2011 4:12 am
Re: Today's (12/31/2012) 7x7 difficult
Glad to see not just me - 1^ last cage I completed and was going crazy going over rest to make sure hadn't made any errors

Posted on: Mon Dec 31, 2012 10:10 am

Posts: 2313
Joined: Thu May 12, 2011 11:58 pm
Re: Today's (12/31/2012) 7x7 difficult
Yes, this was reported by many people, seeing it only now (8.09am here),
my first guess is also no overflow in the generator/solver, but overflow
in the code that's running in the browser.

Edit: this turns out to have been the case.

The problem has been "solved" now by a hack: if a cage has the ^ operator,
and 1 as the result, and there's a 1 in there somewhere, it is approved..
(should work )

Posted on: Mon Dec 31, 2012 1:41 pm

Posts: 193
Joined: Tue May 24, 2011 4:55 pm
Re: Today's (12/31/2012) 7x7 difficult
pnm wrote:
The problem has been "solved" now by a hack: if a cage has the ^ operator,
and 1 as the result, and there's a 1 in there somewhere, it is approved..
(should work )

That hack has a very human, reasoning-rather-than-just-calculating feel to it. Your seem to be on your way to developing strong AI here

Happy new year – hopefully with lots of new subscribers!

Posted on: Mon Dec 31, 2012 1:45 pm

Posts: 2313
Joined: Thu May 12, 2011 11:58 pm
Re: Today's (12/31/2012) 7x7 difficult
bram wrote:
That hack has a very human, reasoning-rather-than-just-calculating feel to it. Your seem to be on your way to developing strong AI here

Yes, I'm waiting for the site to become self-aware

Posted on: Tue Jan 01, 2013 5:06 am

Posts: 4
Joined: Tue Sep 11, 2012 1:16 pm
Re: Today's (12/31/2012) 7x7 difficult
pnm wrote:
The problem has been "solved" now by a hack: if a cage has the ^ operator,
and 1 as the result, and there's a 1 in there somewhere, it is approved.

There are other cases that could still cause trouble. E.g. for an "8^" cage with 6 elements, you could have 8 = 2^3^1^7^7^7, but the 7^7^7 would cause an overflow.

Posted on: Tue Jan 01, 2013 3:01 pm

Posts: 2313
Joined: Thu May 12, 2011 11:58 pm
Re: Today's (12/31/2012) 7x7 difficult
nylimb wrote:
There are other cases that could still cause trouble. E.g. for an "8^" cage with 6 elements, you could have 8 = 2^3^1^7^7^7, but the 7^7^7 would cause an overflow.
Absolutely. That shows the drawback of putting in a hack..

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