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testing no-op puzzles
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Posted on: Mon Jul 15, 2013 9:06 pm

Posts: 188
Joined: Thu May 12, 2011 11:51 pm
Re: testing no-op puzzles
A few extra seconds devoted to an unnecessary end. Why not simplify?

Posted on: Mon Jul 15, 2013 11:17 pm

Posts: 233
Joined: Fri Jun 17, 2011 8:15 pm
Re: testing no-op puzzles
beaker wrote:
I too do not put them in until I have all the cells filled........but,I don't know why this bring discussed........What did I miss

I think the idea is that if you end up with [1,6] in a two cell cage labeled 5, then it must be subtraction; [2,3] or [1,4] must be addition. So why force its entry. In addition, [1,5] could be for either multiplication or division, so which should you enter?

Posted on: Mon Jul 15, 2013 11:22 pm

Posts: 2334
Joined: Thu May 12, 2011 11:58 pm
Re: testing no-op puzzles
jaek wrote:
In addition, [1,5] could be for either multiplication or division, so which should you enter?

Either will work.

At the moment a solution will be approved if all cages have an operator
that produces the target result (and all rows/columns have 1..6 etc.)

Posted on: Tue Jul 16, 2013 12:10 am

Posts: 233
Joined: Fri Jun 17, 2011 8:15 pm
Re: testing no-op puzzles
pnm wrote:
jaek wrote:
In addition, [1,5] could be for either multiplication or division, so which should you enter?

Either will work.

At the moment a solution will be approved if all cages have an operator
that produces the target result (and all rows/columns have 1..6 etc.)

Which is as it should be. It does introduce a trivial argument for non-uniqueness of the solution, though - the placement of the numbers is still unique, but the designation of operators might not be. I suppose you could add a restriction specifying how many of each operator a given puzzle requires. The 14 Jul 2013 puzzle could specify either {4 +, 2 -, 6 *, 1 /} or {4 +, 0 -, 6 *, 3 /} and then the operations and operands could be unique.

Note: I'm not advocating this, just thinking out loud. It would certainly take things in the opposite direction from skipping the operations entirely. Not that I'm advocating skipping the operations either. As far as benevolent dictatorships go, calcudoku.org is one of the best I've been a part of so whatever Patrick decides is fine by me. (And no he didn't ask me to say that. Again, just thinking out loud. I should go solve some puzzles instead.)

Posted on: Tue Jul 16, 2013 12:22 am

Posts: 2334
Joined: Thu May 12, 2011 11:58 pm
Re: testing no-op puzzles
jaek wrote:
Which is as it should be. It does introduce a trivial argument for non-uniqueness of the solution, though - the placement of the numbers is still unique, but the designation of operators might not be.

Yes. There was some discussion about that when the no-ops started.
(I can generate them so the operators are also unique)
jaek wrote:
(And no he didn't ask me to say that. Again, just thinking out loud. I should go solve some puzzles instead.)

Welcome to the dark world of calcudoku.org, where shills further
my agenda in exchange for bonus points

Posted on: Tue Jul 16, 2013 4:13 am

Posts: 98
Joined: Fri May 13, 2011 12:48 am
Re: testing no-op puzzles
beaker wrote:
I too do not put them in until I have all the cells filled........but,I don't know why this bring discussed........What did I miss

It seems to be two things; The annoyance factor of having to go back and input the operators after the puzzle is completed, and the fact that it is not a perfect puzzle because the operators are not unique.

Oh, guess this was discussed, ignore post than.

Posted on: Tue Jul 16, 2013 9:31 am

Posts: 2334
Joined: Thu May 12, 2011 11:58 pm
Re: testing no-op puzzles
picklepep wrote:
It seems to be two things; The annoyance factor of having to go back and input the operators after the puzzle is completed, and the fact that it is not a perfect puzzle because the operators are not unique.

Oh, guess this was discussed, ignore post than.

The first issue (having to put the operators) is a new one though, which I can fix.

(not straight forward, I can't simply ignore the "cage check", but will have to try
all four operators for each, and flag a cage as ok if there is at least one that works)

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